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Problem

Given the roots of two binary trees p and q, write a function to check if they are the same or not.

Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.

Constraints

  • The number of nodes in both trees is in the range [0, 100].
  • -104 <= Node.val <= 104

Solution

The problem Same Tree can be solved using a recursion. To note, implementations using recursion or stack performs a depth-first search and an implementation using queue performs a breadth-first search.

Implementation

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution
{
  public:
    bool isSameTree(TreeNode *p, TreeNode *q)
    {
        if (p == NULL || q == NULL)
            return p == q;

        return p->val == q->val && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
    }
};