Roman to Integer
Problem
Roman numerals are represented by seven different symbols: I
, V
, X
, L
, C
, D
and M
.
Symbol Value
I 1
V 5
X 10
L 50
C 100
D 500
M 1000
For example, 2
is written as II
in Roman numeral, just two ones added together. 12
is written as XII
, which is simply X + II
. The number 27
is written as XXVII
, which is XX + V + II
.
Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII
. Instead, the number four is written as IV
. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX
. There are six instances where subtraction is used:
I
can be placed beforeV
(5) andX
(10) to make 4 and 9.X
can be placed beforeL
(50) andC
(100) to make 40 and 90.C
can be placed beforeD
(500) andM
(1000) to make 400 and 900.
Given a roman numeral, convert it to an integer.
Constraints
1 <= s.length <= 15
s
contains only the characters('I', 'V', 'X', 'L', 'C', 'D', 'M')
.- It is guaranteed that
s
is a valid roman numeral in the range[1, 3999]
.
Solution
The problem Roman to Integer
can be solved using an implemetation of string parser that handles each roman numerals.
Implementation
class Solution
{
public:
int romanToInt(string s)
{
int ret = 0;
for (int i = 0; i < s.length(); i++)
{
if (s[i] == 'I')
ret += 1;
else if (s[i] == 'V')
ret += (ret % 5 == 0) ? 5 : 3;
else if (s[i] == 'X')
ret += (ret % 10 == 0) ? 10 : 8;
else if (s[i] == 'L')
ret += (ret % 50 == 0) ? 50 : 30;
else if (s[i] == 'C')
ret += (ret % 100 == 0) ? 100 : 80;
else if (s[i] == 'D')
ret += (ret % 500 == 0) ? 500 : 300;
else if (s[i] == 'M')
ret += (ret % 1000 == 0) ? 1000 : 800;
}
return ret;
}
};