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Problem

A binary watch has 4 LEDs on the top to represent the hours (0-11), and 6 LEDs on the bottom to represent the minutes (0-59). Each LED represents a zero or one, with the least significant bit on the right.

  • For example, the below binary watch reads “4:51”.

Given an integer turnedOn which represents the number of LEDs that are currently on (ignoring the PM), return all possible times the watch could represent. You may return the answer in any order.

The hour must not contain a leading zero.

  • For example, "01:00" is not valid. It should be "1:00".

The minute must be consist of two digits and may contain a leading zero.

  • For example, "10:2" is not valid. It should be "10:02".

Constraints

  • 0 <= turnedOn <= 10

Solution

The problem Binary Watch can be solved by iterating through all combinations of possible time and checking if the sum of number of bits for hour and minute is equal to turnedOn.

Implementation

class Solution
{
  public:
    vector<string> readBinaryWatch(int turnedOn)
    {
        vector<string> ret;
        for (int hour = 0; hour < 12; hour++)
            for (int minute = 0; minute < 60; minute++)
            {
                if (bitset<4>(hour).count() + bitset<6>(minute).count() != turnedOn)
                    continue;

                char str[6];
                sprintf(str, "%d:%02d", hour, minute);
                ret.push_back(str);
            }

        return ret;
    }
};